A recurrence has the general solution an=c1⋅2n+c2⋅3n.a_n = c_1 \cdot 2^n + c_2 \cdot 3^n.an=c1⋅2n+c2⋅3n.
Given a2=13a_2 = 13a2=13 and a3=35a_3 = 35a3=35, find a0a_0a0.
a0=2a_0 = 2a0=2
a0=3a_0 = 3a0=3
a0=4a_0 = 4a0=4
a0=5a_0 = 5a0=5