A particle's velocity is given by v(t)=∫0te−u2duv(t) = \int_0^t e^{-u^2} duv(t)=∫0te−u2du. What is the acceleration a(t)a(t)a(t) at t=1t=1t=1?
e−1e^{-1}e−1
2/e2/e2/e
1/e1/e1/e
−2/e-2/e−2/e