A hyperbola has vertices at (±3,0)(\pm 3, 0)(±3,0) and foci at (±5,0)(\pm 5, 0)(±5,0). What is the equation?
x^2/9 - y^2/16 = 1
x^2/16 - y^2/9 = 1
y^2/9 - x^2/16 = 1
x^2/25 - y^2/9 = 1