A hollow torus (donut-shaped tank) with major radius $R = 5$ meters and minor radius $r = 1$ meter is oriented vertically. Water leaks out of a small hole of area $a = 0.01$ m$^2$ at the bottom of the torus under the influence of gravity ($g = 10$ m/s$^2$). By Torricelli's Law, the rate of change of water volume is $\\frac{dV}{dt} = -a \\sqrt{2gh}$, where $h$ is the current height of the water level from the bottom hole. When the water level is exactly at the center of the torus ($h = r = 1$ meter), what is the rate of change of the water height $\\frac{dh}{dt}$ in meters per minute?