A function is evaluated along the curve: f(x,y)=x2+xy+y2f(x,y) = x^2 + xy + y^2f(x,y)=x2+xy+y2 where x(t)=1+2tx(t) = 1 + 2tx(t)=1+2t and y(t)=ety(t) = e^ty(t)=et. Find dfdt\frac{df}{dt}dtdf at t=0t = 0t=0.
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