A function fff transforms xxx by f(x)=x4+1f(x) = \frac{x}{4} + 1f(x)=4x+1. What is the inverse function f−1(x)f^{-1}(x)f−1(x)?
f−1(x)=4x−1f^{-1}(x) = 4x - 1f−1(x)=4x−1
f−1(x)=4(x−1)f^{-1}(x) = 4(x - 1)f−1(x)=4(x−1)
f−1(x)=14x−1f^{-1}(x) = \frac{1}{4}x - 1f−1(x)=41x−1
f−1(x)=4x+1f^{-1}(x) = 4x + 1f−1(x)=4x+1