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Derivativeshard
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A function fff is differentiable and f(x+y)=f(x)f(y)f(x+y) = f(x)f(y)f(x+y)=f(x)f(y). If f′(0)=1f'(0) = 1f′(0)=1, find f′(x)f'(x)f′(x).