A dry riverbed accumulates sediment at a rate of $2.50 \text{ g}/(\text{m}^2\cdot\text{year})$. Express this rate in metric tons per square kilometer per day ($\text{t}/(\text{km}^2\cdot\text{day})$). (Take $1 \text{ metric ton} = 10^6 \text{ g}$ and $1 \text{ year} \approx 365.25 \text{ days}$)