Real-World Applicationshard
0:00.0

A dense spherical ore body has an excess mass of DeltaM=3times109\\Delta M = 3 \\times 10^9 kg and is buried at depth z=100z = 100 m. The vertical gravity anomaly directly above the sphere is Deltag=fracGDeltaMz2\\Delta g = \\frac{G \\Delta M}{z^2}, where G=6.67times1011G = 6.67 \\times 10^{-11} m3^3/(kg\cdot s2^2). What is the gravity anomaly Deltag\\Delta g in microgals (1textmutextgal=1081 \\text{ }\\mu\\text{gal} = 10^{-8} m/s2^2)?