The arithmetic mean is $87.5$, which is higher than the salaries of $7$ out of the $8$ employees.

A $12.5\%$ trimmed mean (which trims $1$ value from each end) is $51.67$, which is much closer to the typical employee salary.

The median is $51.0$, which is also highly robust against the outlier.

Trimming the dataset reduces the impact of both the low outlier ($40$) and the high outlier ($350$), resulting in a mean that is closer to the median.