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Differential Equationsmedium
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A cup of liquid at 80∘C80^{\circ}C80∘C is placed in a room at 20∘C20^{\circ}C20∘C. If the temperature follows dTdt=−0.1(T−20)\frac{dT}{dt} = -0.1(T - 20)dtdT​=−0.1(T−20), what is the temperature at t=10t=10t=10?