Ononot — A 3 \times 4 augmented matrix reduces to: \begin{bmatrix} 1

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Linear Systemshard

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A $3 \times 4$ augmented matrix reduces to: $\begin{bmatrix} 1 & 0 & 2 & 1 & | & 4 \\ 0 & 1 & -1 & 0 & | & 3 \\ 0 & 0 & 0 & 0 & | & 0 \end{bmatrix}$

Which vector is a valid basis vector for the null space (homogeneous solution)?